Question

Please Help. Appreciate it for at least trying. Will Medal.

Answer 1

Not sure how to write the formula for perimeter of a cross section

Answer 2

hi could u plz help me with my question i lost ill medal u

Answer 3

lol ok tag me

Answer 4

@zepdrix Could you help me? Thanks

Answer 5

the perimeter of a square
a square has 4 even sides,
the perimeter is the sum of all the sides
P=s+s+s+s = 4s

Answer 6

length and girth must be a max of 90 in

hence
L+4s =90

volume of the rectangular box would be
V=s*s*L --- length* width*height

Answer 7

ok thanks. So for Restraint, should I use the formula for Perimeter of a Cross Section = 4s+L=90 ?

Answer 8

@sooobored

Answer 9

volume would be= s^2*L right?

Answer 10

your restraint is the sum of the length and the girth

girth is just defined as the perimeter of the cross-sectional area

cross sectional area happens to be a square

the perimeter of a square happens to be 4s

formula of the perimeter of a square cross section would be P=4s

formula of your restraint would be 90=L+Girth= L+4s

Answer 11

and yes, volume = s^2 L

Answer 12

thanks, so now I found the derivative of the volume which is 180s-12s^2. I set equal to zero, s=0 , s=15.
Is this correct?

Answer 13

assuming you did the derivation correctly, cause i didnt actually do the problem

a side length of 0 is not a valid answer
hence s=15 would be your only solution

Answer 14

so L=30

Answer 15

Thanks it was correct! @sooobored