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What is the average value of the function f(x)=[4(x^2+1)]/x^2 on the interval [1,3]?
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i think its integral divided by the length of interval
yeah but do i need to find the derivative or just use tht??
so you integrate f(x) from 1 to3, then divde by 2
is tht the derivative??
no, you need to integrate, not differentiate
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wait, let me double check
ok thx
yep, you integrate, not differentiate f(x)
oh okay, so even if it's just a normal function you would still integrate it?
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