Question

Which ordered pair is a solution to this equation?

(x+3)y=14

(11, 1)

(3, 2)

(5, 2)

(7, 2)

Answer 1

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Answer 2

Alrighty

Answer 3

k (11, 1)
(11 + 3)(1) = 14
14(1) = 14
14 = 14\[\rlap{\style{ fontFamily:segoe; background:rgba(0, 0, 0, 0.); //outline:rgba(0, 255, 0, 0.4) solid 5px; \text-shadow: 1px 1px 20px , 0 0 50px violet, 0 0 80px red; \color:black; font-size: 40px; font-weight:bold; padding:30px; border:rgba(0, 255, 0, 0.6) solid 0px; } { \normalsize\cal \color {white} {{}}}}{\style{ fontFamily:segoe; background:rgba(0, 0, 0, 0.); //outline:rgba(0, 255, 0, 0.4) solid 5px; \text-shadow: 1px 1px 20px , 0 0 5px violet, 0 0 0px pink; \color:black; font-size: 40px; font-weight:bold; padding:35px; border:rgba(0, 255, 0, 0.6) solid 0px; } { \normalsize\cal \color {red} {{(11'1)(11+3)(1)=14~~~14(1)=14~~~14=14~~~Plug~ It~ In}}}}\]

Answer 4

That makes sence, thanks

Answer 5

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Answer 6

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