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Mathematics 15 Online
OpenStudy (iwanttogotostanford):

htions!

OpenStudy (iwanttogotostanford):

I REALLY Need help i don't get them!

OpenStudy (iwanttogotostanford):

these 2!

OpenStudy (danjs):

i thought you did these two already

OpenStudy (iwanttogotostanford):

no i didnt i reallyuuyyyy need help man, please !@DanJS

OpenStudy (iwanttogotostanford):

@DanJS

OpenStudy (danjs):

ok, derivative tells you the instantaneous slope, y ' = 5/x^2 when x is 5, y'=5/25=1/5

OpenStudy (raffle_snaffle):

I have no clue. Dan is your man!

OpenStudy (danjs):

for f(x)=2x + 2 over interval [-3,4] average rate of change is the slope of a line through the endpoints... \[\frac{ f(4)-f(-3) }{ 4-(-3) }\]

OpenStudy (iwanttogotostanford):

14...?

OpenStudy (iwanttogotostanford):

/..

OpenStudy (danjs):

nah, try again...

OpenStudy (iwanttogotostanford):

2/7 then!

OpenStudy (iwanttogotostanford):

i really don't know that much this i s my last question and i just am not 100% sure.

OpenStudy (danjs):

\[\frac{ 10-(-4) }{ 4-(-3) }=\frac{ 14 }{ 7 }=2\]

OpenStudy (iwanttogotostanford):

oh wow. simple. thank yay

OpenStudy (danjs):

welcome

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