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Can someone help me with this calculus problem? I think the answer to part c is y - 6 = 3(x - 4).
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d/dx 3 (f(x))^2 = 3 * 2f(x) * f'(x) (using chain rule) now we plug in x = 4 slope of tangent line = 6 * f(4) * f'(4) = 6 * 6 * 3 = 108
he is right
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