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OpenStudy (itrymath):
OpenStudy (itrymath):
@DanJS @Jamierox4ev3r
OpenStudy (itrymath):
A
OpenStudy (danjs):
So you need to multiply those two measures together to get the Area
OpenStudy (itrymath):
i dont know how
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OpenStudy (itrymath):
I mean i do but i get an answer of 12.something
OpenStudy (danjs):
\[\large \sqrt[3]{81}*3^{\frac{ 2 }{ 3 }}\]
to be able to multiply those together, they need to have the same bases, notice 81=3*3*3*3
\[\large \sqrt[3]{81}*3^{\frac{ 2 }{ 3 }}=\sqrt[3]{3^4}*3^\frac{ 2 }{ 3 }\]
OpenStudy (itrymath):
oh so A
OpenStudy (danjs):
the roots are the same as the fraction exponents, sqrt(a)=a^(1/2)
\[\huge 3^{\frac{ 4 }{ 3 }}*3^{\frac{ 2 }{ 3 }}\]
ganeshie8 (ganeshie8):
Seeing 81 = 3*3*3*3 might be hard, but you must be knowing 81 = 9*9 ?
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OpenStudy (itrymath):
so im correct A
OpenStudy (danjs):
no, remember you have to add exponents when you multiply like bases together
OpenStudy (danjs):
\[\huge 3^\frac{ 6 }{ 3 }=3^2=9\]
OpenStudy (itrymath):
i thought we multiply 4 and 2 .... well i guess we dont. Learned something new!! thanks dan
OpenStudy (danjs):
exponent raised to exponent, multiply
\[\huge [b^n]^m=b^{m*n}\]
multiplying same bases, add exponents
\[\huge b^m*b^n=b^{m+n}\]