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Mathematics 29 Online
OpenStudy (itrymath):

hi

OpenStudy (itrymath):

OpenStudy (itrymath):

@DanJS @Jamierox4ev3r

OpenStudy (itrymath):

A

OpenStudy (danjs):

So you need to multiply those two measures together to get the Area

OpenStudy (itrymath):

i dont know how

OpenStudy (itrymath):

I mean i do but i get an answer of 12.something

OpenStudy (danjs):

\[\large \sqrt[3]{81}*3^{\frac{ 2 }{ 3 }}\] to be able to multiply those together, they need to have the same bases, notice 81=3*3*3*3 \[\large \sqrt[3]{81}*3^{\frac{ 2 }{ 3 }}=\sqrt[3]{3^4}*3^\frac{ 2 }{ 3 }\]

OpenStudy (itrymath):

oh so A

OpenStudy (danjs):

the roots are the same as the fraction exponents, sqrt(a)=a^(1/2) \[\huge 3^{\frac{ 4 }{ 3 }}*3^{\frac{ 2 }{ 3 }}\]

ganeshie8 (ganeshie8):

Seeing 81 = 3*3*3*3 might be hard, but you must be knowing 81 = 9*9 ?

OpenStudy (itrymath):

so im correct A

OpenStudy (danjs):

no, remember you have to add exponents when you multiply like bases together

OpenStudy (danjs):

\[\huge 3^\frac{ 6 }{ 3 }=3^2=9\]

OpenStudy (itrymath):

i thought we multiply 4 and 2 .... well i guess we dont. Learned something new!! thanks dan

OpenStudy (danjs):

exponent raised to exponent, multiply \[\huge [b^n]^m=b^{m*n}\] multiplying same bases, add exponents \[\huge b^m*b^n=b^{m+n}\]

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