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@DanJS
Tried anything ?
I actually dont understand how to do this
use the power raised to power property i just put in last time
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B
what does that give ya after multiplying the powers?
2 over 18 or 5 over 6
The two things to use on this one are .. \[\huge [b^v]^u=b^{u*v}\] \[\huge \sqrt[n]{b}=b^\frac{ 1 }{ n }\]
Yes, I know but
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right 2/18, that reduces to 1/9
OH You reduce it
i totally forgot that
then use the second property to change the 1/9 power into a root.. \[\huge 3^{1/9}=\sqrt[9]{3}\]
yeah i know from there
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omg thanks so much!!
welcome, just have to remember those properties for the patterns
I do.. @DanJS
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