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Find the perimeter of a square having two consecutive vertices at (7, 2) and (-3, 3).
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Maybe 4sqrt101
Find the distance between the two points, then that is the length of one side, then the perimeter is 4 times that number. The distance between \((x_1,y_1)\) and \((x_2,y_2)\) is given by \[D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\]
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