Question

Solve for w.
(w+2)^2 = 2w^2 +2w-4

Answer 1

\[(w+2)^{2}=2w ^{2}+2w-4\]

Answer 2

start by expanding (w+2)^2

what do you get?

Answer 3

w^2+4x+4

Answer 4

good!

now we write:

w^2+4x+4 = 2w^2 +2w-4

then we combine like terms

Answer 5

w^2 - 2w - 8 = 0

Answer 6

i understand that part then we factor it out after this right?

Answer 7

yes, good!

do you know what that factors to?

Answer 8

2 and -4?

Answer 9

good!

so we have

(w-4)(w+2) = 0

so w = ?

Answer 10

w=-2 and 4?

Answer 11

good job!

Answer 12

Thank you so so so much!!!!!