Question

One side of a triangle is 15 inches, and the area of the triangle is 90 sq. inches. Find the area of a similar triangle in which the corresponding side is 9 inches.

Answer 1

set up the proportion, while letting x be the area of the similar triangle:
(15^2)/(9^2) = (90)/(x) <~~~length squared over length squared equals area over area
x = [(90)(9^2)]/(15^2) <~~~~Simplify

So the answer is x = 32.4 sq. in.