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What are the odds of rolling two number cubes and getting a sum of seven?
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We assume that the two number cubes are six-sided and numbered from 1 to 6, AND that they are fair cubes. |dw:1479343767558:dw| Complete the table of outcomes and count how many 7's are in the table. Divide by the total number of outcomes, 6\(\times\)6=36 to get the probability.
Oh, by the way, odds are the ratio between success and failure. Suppose there are x successes, and 36-x failures, the odds are x:36-x, reduced to the simplest (integer) terms.
alright, thanks for the help! :)
You're welcome! :)
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