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Mathematics 8 Online
OpenStudy (goho2838):

Easy function

OpenStudy (goho2838):

OpenStudy (harman.singh):

Could you show your working out for f(x)=-1 please?

OpenStudy (goho2838):

I just guessed so I don't know

OpenStudy (harman.singh):

What was your equation for the line?

OpenStudy (goho2838):

Y=1x+-3?

OpenStudy (harman.singh):

I think your gradient is wrong. Did you use the rise/run formula correctly?

OpenStudy (harman.singh):

\[m=\frac{ y2-y1 }{ x2-x1 }\]

OpenStudy (harman.singh):

Did you guess a) as well because you would not have gotten '1' with the equation you posted above?

OpenStudy (goho2838):

Would I do 1*-1+-3

OpenStudy (harman.singh):

For b), you would need to let your y-value equal to -1 and then solve for x. -1=mx+c

OpenStudy (harman.singh):

Before you do that, you need to have the correct gradient. Do you know how to find the gradient of a line?

OpenStudy (goho2838):

Stop being an itch and just give me the answer

OpenStudy (harman.singh):

I am not allowed to give you the answer but guide you to it...

OpenStudy (harman.singh):

You don't need to be rude

OpenStudy (harman.singh):

If you don't want my help, let me know and I will leave

OpenStudy (goho2838):

Ride my ock have a good night

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