Question

How many liters of pure water should be mixed with a 8-L solution of 90 % acid to produce a mixture that is 60% water ?

Answer 1

@mathmate
@3mar

Answer 2

x= pure water concetration

Answer 3

0.9(8-x )

Answer 4

For the last one, your presentation of the problem is awesome and the formed equation is correct!

You are very good!
Keep that on!

Now for this one!

Answer 5

I don't know if that makes sense..

Answer 6

oh thanks!

Answer 7

yeah now for this one...

Answer 8

90 % acid: means it contains 10 % water or what?

Answer 9

initially i guess, but at the end the C of water must be changed to 60%

Answer 10

I kow, just want to know about the acid

Answer 11

C= X/V

Answer 12

8(0.1) = x right ?

Answer 13

initially 0.8 liters of water

Answer 14

Could you give me just 2 min, please?

Answer 15

0.8 + x = 0.6/x i dont know if that is right..

Answer 16

if I'm right could you medal me, I'll medal you anyway...

Answer 17

is it right ?

Answer 18

d