Question

PLS HELP FINALS IN MORNING

Answer 1

Could I help you?

Answer 2

@3mar
Please do

Answer 3

Of course.
My pleasure.

Answer 4

\(\color{black}{\displaystyle \frac{a^x}{b^{3-x}} \times \frac{b^y}{(a^{y+1})^2} =ab^6 }\)

\(\color{black}{\displaystyle \left(a^xb^{x-3}\right)\times b^ya^{-2y-2} =ab^6 }\)

\(\color{black}{\displaystyle a^{x-2y-2}b^{x-3+y}=ab^6 }\)

Answer 5

then set a system to solve it.
```
x-2y-2=1 (equating a's exponents)
x-3+y=6 (equating b's exponents)
```

Answer 6

Solomon your steps aren't really explained, more so expected he understands law of indices

Answer 7

The idea is :



and I think this would help you.