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x^2-4x+3
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maximum or minimum?
can you tell me what maximum and minimum is??
Did you take the derivatives?
@bizzybone67 Do you follow?
\(\color{black}{\displaystyle x^2-4x+3=(x-1)(x-3) }\) \(\color{black}{\displaystyle \frac{d}{dx}(x^2-4x+3)=2x-4 }\) \(\color{black}{\displaystyle \int(x^2-4x+3)~dx=\frac{x^3}{3}-2x^2+3x+\color{grey}{\rm C} }\) \(\color{black}{\displaystyle x^2-4x+3=(x-2)^2-1 }\)
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Just a polynomial ... so I posted a few things you can do with it.
B-b: where are the instructions for this problem? With no instructions from you, the rest of us have to guess what your goal is. Not good.
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