Question

Help please

Answer 1

@amorfide

Answer 2

you can't take the square root of a negative number
so for the first one solve \[6-x\geq 0\] for \(x\) in one step

Answer 3

would it be -6x?

Answer 4

no

Answer 5

\[6-x\geq 0\] add \(x\) to both sides

Answer 6

oh so 6>x

Answer 7

because the x cancels out right

Answer 8

@mathstudent55

Answer 9

@mathmale

Answer 10

\[6 \geq x,x \leq 6\]
domain is \[(-\infty ,6] \]

Answer 11

Range is \[[0,\infty )\]

Answer 12

because \[g(y)=\sqrt{y},\]
if \[y \geq 0\]