OpenStudy (please.help.me):

Write the expression as the sine, cosine, or tangent of an angle. tan 35° − tan 15°/1 + tan 35° tan 15°

11 months ago
OpenStudy (please.help.me):

Write the expression as the sine, cosine, or tangent of an angle.\[\frac{ \tan 35° − \tan 15° }{ 1 + \tan 35° \tan 15° }\]

11 months ago
OpenStudy (3mar):

Do you mean: \[\Large \frac{ \tan 35° − \tan 15°}{ 1 + \tan 35° \tan 15° }=~?~?\]

11 months ago
OpenStudy (steve816):

|dw:1479781253157:dw| See any patterns?

11 months ago
OpenStudy (please.help.me):

Yes, it says to write the expression as the sine, cosine, or tangent of an angle.

11 months ago
OpenStudy (3mar):

I think this would help you.

11 months ago
OpenStudy (please.help.me):

It's tan (A-B) right?

11 months ago
OpenStudy (steve816):

Yup

11 months ago
OpenStudy (steve816):

A = 35 and B = 15

11 months ago
OpenStudy (3mar):

Yes, where A=35 and B=15

11 months ago
OpenStudy (mathmale):

So, how would you find tan (35 deg-15deg)? That's tan 20 deg.

11 months ago
OpenStudy (please.help.me):

So then do I just plug it into the calculator?

11 months ago
OpenStudy (steve816):

^ That is pretty much the answer.

11 months ago
OpenStudy (steve816):

It just says to write the expression.

11 months ago
OpenStudy (mathmale):

I'd suggest you not use the calc. in this case. As Steve stay, rewrite the given expression in the simplest form possible. See my previous comment.

11 months ago
OpenStudy (please.help.me):

So the answer is tan(20) ?

11 months ago
OpenStudy (3mar):

\[\Huge\color{Coral}\checkmark\]

11 months ago
OpenStudy (please.help.me):

That was marked wrong

11 months ago
OpenStudy (please.help.me):

@3mar

11 months ago
OpenStudy (steve816):

Well, it is right...

11 months ago
OpenStudy (3mar):

why?

11 months ago
OpenStudy (please.help.me):

I will insert a screenshot

11 months ago
OpenStudy (please.help.me):

11 months ago
OpenStudy (please.help.me):

@3mar ^

11 months ago
OpenStudy (3mar):

\[\Huge\color{LightSkyBlue }ツ\] Where is the "degree" sign?

11 months ago
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