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\[y=\frac{ 1 }{ \sqrt{8} }x^2 ...(1)\] \[y=\sqrt{x} ...(2)\] from (1) and (2) \[\sqrt{x}=\frac{ 1 }{ \sqrt{8} }x^2\] squaring \[x=\frac{ x^4 }{ 8 },x^4=8x,x^4-8x=0\] \[x(x^3-8)=0,x=0 \] \[x^3-8=0,x^3=8=2^3,x=2\] when x=0,y=0 when x=2 \[y=\sqrt{2}\] so point of intersection is \[\left( 0,0 \right)~and~\left( 2,\sqrt{2} \right)\]
|dw:1480001403941:dw| \[reqd. area=\int\limits_{0}^{2}\left[ \sqrt{x}-\frac{ 1 }{ \sqrt{8} }x^2 \right]dx\] can you complete it?
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