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Mathematics 13 Online
OpenStudy (marcelie):

help please find the following indefinite integral

OpenStudy (marcelie):

|dw:1480109636981:dw|

OpenStudy (marcelie):

i was thinking of partial fractions ?

OpenStudy (marcelie):

@SolomonZelman

OpenStudy (irishboy123):

yes \(\dfrac{1}{x^3 - x} = \dfrac{1}{x(x^2 - 1)} = \dfrac{1}{x(x - 1)(x+1)}\)

OpenStudy (marcelie):

would it be wrong if i did it like this ? |dw:1480110967468:dw|

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