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The question is in the comments The problem was generated from problems like the ones on http://saab.org
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Scratch all that, triangles BQP and AQD are similar. So BP = AD. PD is the hypotenuse of the right triangle PDC whose sides are known. |dw:1480171080578:dw|
OK on the similar triangle idea, but you need congruent, don't you?
we can do this: |dw:1480172732925:dw|
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