Question

I am only getting 1/2 the question right... problem is attached. Please help!

Answer 1

Hey Amy, your answer is correct but incomplete. For this question, you should get two values for x.

x=121/2 & x=...

Answer 2

Here is the quadratic formula:
\[x=\frac{ -b \pm \sqrt{b^2 -4ac} }{ 2a }\]
To get two x values, you would need to solve for both positive and negative square root as follow:
\[x=\frac{ -b+\sqrt{b^2 -4ac} }{ ?2a}\]

and...

\[x=\frac{ -b-\sqrt{b^2 -4ac} }{ ?2a}\]

Answer 3

For the '+ sqroot' equation (1st one) you would have got 121/2. You need to solve for the second equation to get the second x-value.