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I am only getting 1/2 the question right... problem is attached. Please help!
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Hey Amy, your answer is correct but incomplete. For this question, you should get two values for x. x=121/2 & x=...
Here is the quadratic formula: \[x=\frac{ -b \pm \sqrt{b^2 -4ac} }{ 2a }\] To get two x values, you would need to solve for both positive and negative square root as follow: \[x=\frac{ -b+\sqrt{b^2 -4ac} }{ ?2a}\] and... \[x=\frac{ -b-\sqrt{b^2 -4ac} }{ ?2a}\]
For the '+ sqroot' equation (1st one) you would have got 121/2. You need to solve for the second equation to get the second x-value.
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