Question

Can someone Please help me???

Answer 1

sure! whats the problem?

Answer 2

tf , what grade are u in may i ask?

Answer 3

@steve816

Answer 4

10th

Answer 5

thats why :/ im in 8th :/ steves here to help tho , arent you steve?

Answer 6

@zepdrix @Elsa213

Answer 7

@inkyvoyd @sweetburger

Answer 8

\[\sqrt[3]{-8x^{24}y^{36}}\\
=({-8x^{24}y^{36}})^{1/3}\\
=((-2)^3)^{1/3}(x^{24})^{1/3}(y^{36})^{1/3}\\
= -2^{3/3}x^{24/3}y^{36/3}\\
=\]