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OpenStudy (yuii):
Solve for x. 3x + 2 = 38 A. 12 B. 13.33 C. 108 D. 120
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MARC (marc_d):
Step 1:subtract both sides by 2
MARC (marc_d):
\[3x+2-2=38-2\]
MARC (marc_d):
\[3x=36\]
MARC (marc_d):
Step 2 : Divide both sides by 3 to solve for x..
MARC (marc_d):
what value u get when u divide 36 by 3? @Yuii
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OpenStudy (yuii):
12.
OpenStudy (skypie13):
bravo!
MARC (marc_d):
yeap,that's right!
MARC (marc_d):
therefore,the value of x is 12... x=12
OpenStudy (yuii):
I figured it was 12 but I was just making sure.
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