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Pre calc Conic Sections, need help. What is the eccentricity of the equation below? (x-5)^2 (y+1)^2 ------ + ------- =1 52 64
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\[ c^2=a^2 -b^2\\ e=\frac c a \]]
that first formula is to get the foci points right??
You have a and b, find c then e=c/a
how did you figure that out?
sorry a^2=64 and b^2=52
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\[ \frac{x^2}{a^2}+\frac{y^2}{b^2}=1 \]
C=√116
so √116/8 right?
\[ c^2=64-52=12 \]
\[ c=\sqrt{12} \]
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oops, I added
How much is e?
√12/64 is irrational, but I can match this up to one of the answers, you are awesome.
no \[ \frac{\sqrt {12}}{8}=\frac {\sqrt 3}4 \]
aww, none of my answers match
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oh, over 8, not 8^2, got it
What are your answers?
√3/4 is one of them
That is it
thx
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