Question

Can someone check if my answer is correct?
What are the zeroes of y = x2 + 14x +40 ?

Answer 1

y = 0
0 = x^2 + 14x +40
factors of 14
(a+b) = 14 = -10 -4
(a*b) = 40 = -10* -4

0 = x^2 - 10x - 4x + 40

x = -10
x = -4

y = -10^2 + 14*-10 + 40
y = 0

y = -4*-4 + 14*-4 + 40
y = 0

Answer 2

Yup! I got - 10 and -4 too
Good job!

Answer 3

@steve816 thx!

Answer 4

Welcome!