Question

which functions graph has a vertex at (3,5) and contains the point (5,13)
y = 1/10(x+3)^2 - 5
y= 1/10(x-3)^2 - 5
y= 2(x-3)^2 + 5
y= 2(x+3)^2 + 5

Answer 1

C. y= 2(x-3)^2 + 5

Answer 2

@knwak could u show me the steps?

Answer 3

@Knawk

Answer 4

The all look like this:

y = a(x-h)^2 + k

You are given the vertex. That's (h,k) = (3,5)

y = a(x-3)^2 + 5

All we need it 'a'.

You are given a point. That't (x,y) = (5,13)

13 = a(5-3)^2 + 5

Solve for a. Show us your best algebra.

Answer 5

a would it be 2 ? @tkhunny

Answer 6

I don't know. You tell me - with confidence.