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testing one two \[\sum_{k=1}^{\infty}\frac{1}{k^2}\]
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\[\sum_{k=1}^{\infty}\frac{1}{k^2}\]
p-series P =2 , p > 1 series converges ;)
This site is so slow, the latex won't even load
\(\large\rm \int_a^b \frac{\sin(x)}{x}~dx=whuuuu?\) Ooo it works!
$$ \frac 1 x $$
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??? Oh wait, it loaded
I'm sure Jay is working on getting LaTeX to load faster.
$$\sum_{k=1}^{\infty}\frac{1}{k^2}= \frac{\pi^2}{6}$$
\[\oint_{c}f(x)dz\]
put x not z \[\oint_{c}f(z)dz\]
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