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Express your answer as a polynomial in standard form (3c+2)(c^2−6c−4) . a) 3c^3−20c^2-24c+8 b) 3c^3−16c^2−8 c) 3c^3−12c−8 d) 3c^3−16c^2−24c−8
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its B just simply multiply first 3c with c^2 -6c-4 and then 2 with c^2 -6c-4 and add up i.e. 3c(c^2 -6c-4)+2(c^2 -6c-4)=(3c^3-18c^2-12c) +(2c^2-12c-8)
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