Question

https://gyazo.com/64be057aa2f207eeaacdd2f7cff8f540

Answer 1

Any ideas?

Answer 2

no

Answer 3

@3mar

Answer 4

You have studied limits?

Answer 5

rate of change
\[=\frac{ f(2)-f(0) }{ 2-0 }=?\]

Answer 6

how do i do that @sshayer @3mar

Answer 7

You have studied limits?

Answer 8

no

Answer 9

SO how would I explain that for you?
Did you study the derivatives?

Answer 10

no

Answer 11

You are in grade ..#.. if I may know?

Answer 12

9

Answer 13

so what so you know about the rate of change?

Answer 14

something to do with slope

Answer 15

So you know that "The slope is the rate of change of the function at a certain point"?

Answer 16

ok

Answer 17

idk how 2

but yes iw ill reply faster

Answer 18

ok

Answer 19

idk

Answer 20

no

Answer 21

f'(x=0)

Answer 22

Let me know when you are back!

Answer 23

hi

Answer 24

is it 250 x .5?

Answer 25

f′(0)=250(0)(0.5)0=??

for this^^

Answer 26

and so thats the final answer?

Answer 27

idk

Answer 28

idk

Answer 29

ok

Answer 30

how/ ??

Answer 31

idk how to subtract letters ...

Answer 32

helloo??

Answer 33

The following is the formula for average rate of change:\[AveRateofChange=\frac{ f(b)-f(a) }{ b-a }\]
In this particular oproblem, a=0 and b=2.

The function in question is f(s)=250(0.5)^x.
Evaluate this at x=0 and x=2.

f(2)=?
f(0)=?

f(2)-f(0)=?

Answer 34

\[\frac{ f(b)-f(a) }{ b-a }\]

Here, a=0 and b=2.

Find f(0) and f(2).

Then calculate f(2)-f(0).

Answer 35

\[f(2)=250(.5)^2=250(.25)=62.5\]
\[f(0)=250(.5)^0=250*1=250\]
rate of change\[=\frac{ 62.5-250 }{ 2-0 }=\frac{ -187.5 }{ 2 }=-93.75\]