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Factoring the following by using the grouping method and identify one of the factors below: 28xy − 154x + 20y − 110? A. x − 4 B. 7x + 4 C. 7x − 11 D. 2y − 11
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The is a case where you can group the xy term with either the x or the y term, take out the common factor and everything will fall in place (if the expression is factorizable).
(28xy − 154x) + (20y − 110) =14x(2y-11) + 10(2y-11) = ?
(2y-11) (14x + 10)
Wait, there is another common factor in 14x+10. That has to be taken out as well.
2(7x+5)
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Actually, that "2" should have been taken out before we even began! So the final result looks like ....?
Thank you for all the help you've given me!
welcome ^_^
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