Question

I need help with this question....
Factor the expression 3x^3+4x^2-15x-20. show work.

Answer 1

\[3x^3+4x^2-15x-20\]
\[=\left(3x^3+4x^2\right)+\left(-15x-20\right)\]
\[\mathrm{Factor\:out\:}x^2\mathrm{\:from\:}3x^3+4x^2\mathrm{:\quad }x^2\left(3x+4\right)\]
\[\mathrm{Factor\:out\:}-5\mathrm{\:from\:}-15x-20\mathrm{:\quad }-5\left(3x+4\right)\]
\[=x^2\left(3x+4\right)-5\left(3x+4\right)\]
\[\mathrm{Factor\:out\:common\:term\:}\left(3x+4\right)\]
\[=\left(3x+4\right)\left(x^2-5\right)\]
\[x^2-5=\left(x+\sqrt{5}\right)\left(x-\sqrt{5}\right)\]
\[=\left(3x+4\right)\left(x+\sqrt{5}\right)\left(x-\sqrt{5}\right)\]

Answer 2

I am about to help you please wait before you hand out the medal plz

Answer 3

The awnser I came up with is -6x+2y-20 you have to simplify the expression

Answer 4

we only have a few more weeks of Openstudy but when you answer questions please try and let the asker participate
He/she is not even online according to the system.

Answer 5

thank you DecentNabeel but I don't really get it.
Mrs.ambrose614, triciaal has a point I would like to be explain the presses and I would like to participate in order for me to understand the work. thank you all for trying to help.

Answer 6

@DecentNabeel great ,nice work really !!!

Answer 7

@3mar I need help with this question.

Answer 8

Well, I am here.
Any Help... Any Time...
How could I help you?

Answer 9

Factor the expression 3x^3+4x^2-15x-20 show work.

Answer 10

Any ideas?

I think we will proceed with "grouping"!

Answer 11

so would it be (3x^3+4x^2)+(-15x-20)?

Answer 12

where this would lead you?

Answer 13

x^2(3x+4)-5(3x+4)?

Answer 14

then?

Answer 15

can you take (3x+4) as a common factor?