Question

What is the vertex of the parabola given by the equation below?

x=-4(y-3)^2+2

Answer 1

Hint:
The conventional equation of a parabola in vertex form is:
\(y=a(x-h)^2+k\), where the vertex is at (h,k).
If a is positive, parabola opens upwards.
However, we can turn the parabola 90 degrees, i.e. let the parabola sit sideways, opens left/right, by exchanging x and y to give
\(x=a(y-k)^2+h\), which makes the vertex at again (h,k).
if a is positive, parabola opens to the right.
by comparing the given equation with the standard forms, the solution can be obtained.

Note: a vertex is defined by an ordered pair, like (4,-2) and not a single number.