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HelpMePlz:
The equation of a circle is (x-3)^2+(y+8)^2. Relative to the standard equation of a circle (x^2+y^2=r^2), how has this circle been shifted? What is the radius of the circle?
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Champion:
Hint: Shifting of the centre of a circle by (h,k) from the origin is given by: (x-h)^2+(y-k)^2=r^2
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