Question

The equation of a circle is (x-3)^2+(y+8)^2. Relative to the standard equation of a circle (x^2+y^2=r^2), how has this circle been shifted? What is the radius of the circle?

Answer 1

Hint:
Shifting of the centre of a circle by (h,k) from the origin is given by:
(x-h)^2+(y-k)^2=r^2