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Mathematics 7 Online
OpenStudy (vipulrakta):

help me to solve this question

OpenStudy (vipulrakta):

OpenStudy (akshay18):

do you want solution or concept

OpenStudy (vipulrakta):

concept

OpenStudy (akshay18):

i will tell you concept

OpenStudy (akshay18):

you know kinetic energy changes to quater means its velocity change to 1/2 of intial

OpenStudy (akshay18):

on droping ftom H height on reaching ground its speed will be [2gH]^1/2

OpenStudy (vipulrakta):

what time ball take to come at rest

OpenStudy (akshay18):

i telling you concept if you need ans i will tell you

OpenStudy (akshay18):

4[2g/H]^1/2

OpenStudy (irishboy123):

\(\color{red}{mgH} \to \dfrac{1}{2} m v^2\to \dfrac{1}{4}*\dfrac{1}{2} m v^2\to \color{red}{\dfrac{mgH}{4}} \) \(H \to \dfrac{H}{4} \to \dfrac{H}{16}\) @osprey is right on this. classically, it will never come to rest.

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