can someone help me determine if y=-x^2-1 makes y=0
I awnsered your other quetsion for you now hold on while I figure this one out
could you demonstrate what it means idk what they mean is there an x value you need to plug in and find if the result would be y = 0?
it asks detirmine if the parbola opens up or down (up a larger than 0 down a less than 0 a is -1 and the axis of symmytry
Use the slope form y=Mx+b to find the y intercept b b=0
Y=-x^2-1 makes y=0 I hope I helped you
so axis is on (0, 0)?
Yes it is
Thanks so much!
I used an app called math way to find the awnser
alright y=-x^2-1 this is an even degree parabola the leading coefficent is negative thus the parabola would be upside down the axis of symmetry can be found using -b/2a the equation needs to be adjusted by the order of degrees thus y = -x^2 + 0x - 1 -b/2a -0/-2 axis of symmetry would be zero hope that helps
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