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Mathematics 14 Online
OpenStudy (theoneandonly):

help? http://prntscr.com/dfn8mw

OpenStudy (mathstudent55):

Look up the compound interest formula.

OpenStudy (theoneandonly):

A=1000(1+0.02/4)^(4*5) A=1105 this was my answer

OpenStudy (theoneandonly):

for the first one

OpenStudy (mathstudent55):

\(\Large A = P(1 + \dfrac{r}{n})^{nt}\) \(\Large A = $1000 \left( 1 + \dfrac{0.02}{4} \right) ^{4 \times 5}\) \(\Large A = $1104.90\) You are correct.

OpenStudy (theoneandonly):

ok thank you c:

OpenStudy (theoneandonly):

ill work on the second one

OpenStudy (mathstudent55):

Ok.

OpenStudy (mathstudent55):

Did you get an answer for 2?

OpenStudy (theoneandonly):

this is what I got A=720(1+0.062/2)^(2*5) A=977

OpenStudy (theoneandonly):

@mathstudent55

OpenStudy (theoneandonly):

@princeharryyy

OpenStudy (princeharryyy):

that's right. just calculate.

OpenStudy (theoneandonly):

so is my answer for the second one correct?

OpenStudy (princeharryyy):

yes. I googled ur calculation. it matches ur answer.

OpenStudy (theoneandonly):

ok ty

OpenStudy (princeharryyy):

yw

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