If the emf produced in a wire is 0.88 volts and the wire moves perpendicular to a magnetic field of strength 0.075 newtons/amperes•meter at a speed of 4.20 m/s what is the length of the wire in the magnetic field?
A.) 0.27m
B.) 2.8m
C.)0.020m
D.) 3.7m

Question

If the emf produced in a wire is 0.88 volts and the wire moves perpendicular to a magnetic field of strength 0.075 newtons/amperes•meter at a speed of 4.20 m/s what is the length of the wire in the magnetic field? 
A.) 0.27m
B.) 2.8m
C.)0.020m
D.) 3.7m

irishboy123 · Answer

there is a nifty equation for the EMF $ \mathcal{E} $ generated in a wire length $l$ moving perpndicularly to a B field at constant velocity $v$: $ \mathcal{E} = Blv$ There is a very followable explanation here: http://www.solitaryroad.com/c1048.html And probably loads more over the web. with $l = \dfrac{ \mathcal{E} }{B v}$, .... wonder what the answer might B ?!