Question

What is the explicit rule for this geometric sequence?

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Answer 1

what is the first term?
what is the common ratio?

Answer 2

common ratio- how is 2 related to 6 or how do you get 6 from 2?

Answer 3

the answer would be C:
\[\frac{2}{9}\times 3^{n-1}\]
\[n=1,2,3,4...\]
\[\frac{2}{9}\times 3^{1-1}=\frac{2}{9}\]
\[\frac{2}{9}\times 3^{2-1}=\frac{2}{3}\]
\[\frac{2}{9}\times 3^{3-1}=2\]
\[\frac{2}{9}\times 3^{4-1}=6\]
And so on...