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Sketch the graph of
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\(y^{2}=x(1-x^{2})\)
@Angle @kittybasil
i got the value of x...
when y=0, x(1-x^2)=0
x=0
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\(1-x^{2}\)=0
\(x^{2}=1\)
\(x=+-\sqrt{1}\)
\(x=1\)
\(x=-1\)
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i'm not sure what to do next...
when i tried using desmos graphing calculator,the shape of the graph looks a bit weird for me... xD I don't get it...
let's see \(y^{2}=x-x^{3}\)
\(y=\pm\sqrt{x-x^{3}}\)
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