Question

Hi im doing a project on natural parabolas, and i have to graph one in standard form (ax+bx+c) can you help me with the math, im doing a mountain which has a peak of 12,389 so my vertex is (0 , 12,389) and the x- coordinates are (-328,084, 0) and (328,084, 0) because that is the distance from the bottom ends to each other. if i put it in vertex form y=a(x-h)^2+k i will get y=a(328,084-0)^2+12,389 and to find a after completing the square the final answer was y= -1.15097569e-7(x-0)^2+ 12,389 which is ungraphable what did i do wrong?

Answer 1

@Hero @Luigi0210