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k12user:
Solve. 3y + 15 > –6 A. y > 3 B. y > –7 C. y > 13 D. y > –17
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k12user:
? @Ultrilliam
Ultrilliam:
hang on, im thinking ofhow to explain the answer
k12user:
ok
Ultrilliam:
15-6-2=? we take 1 off of 3 because it needs to be greater then
Ultrilliam:
(and because we are doing this in reverse)
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k12user:
-7?
Ultrilliam:
correct
Ultrilliam:
It's easier to add the negative later :P
k12user:
yay thx. #3 coming right up 😁
k12user:
The solution to which inequality is shown? Number line from negative 10 to 10 , tic marks at every integer , labels at negative 10 , negative 5 , 0 , 5 , 10 , open red circle on negative 4 , red shading to the left of the red circle. A. y + 3 ≥ –1 B. y + 3 > –1 C. y + 3 ≤ –1 D. y + 3 < –1
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Ultrilliam:
Please make it a new question, it improves our search discovery o-o
k12user:
ok
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