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Mathematics 68 Online
k12user:

Solve. 3y + 15 > –6 A. y > 3 B. y > –7 C. y > 13 D. y > –17

k12user:

? @Ultrilliam

Ultrilliam:

hang on, im thinking ofhow to explain the answer

k12user:

ok

Ultrilliam:

15-6-2=? we take 1 off of 3 because it needs to be greater then

Ultrilliam:

(and because we are doing this in reverse)

k12user:

-7?

Ultrilliam:

correct

Ultrilliam:

It's easier to add the negative later :P

k12user:

yay thx. #3 coming right up 😁

k12user:

The solution to which inequality is shown? Number line from negative 10 to 10 , tic marks at every integer , labels at negative 10 , negative 5 , 0 , 5 , 10 , open red circle on negative 4 , red shading to the left of the red circle. A. y + 3 ≥ –1 B. y + 3 > –1 C. y + 3 ≤ –1 D. y + 3 < –1

Ultrilliam:

Please make it a new question, it improves our search discovery o-o

k12user:

ok

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