Question

Test the series for convergence/divergence (check my work please).

Answer 1

\[\sum_{n=0}^{\infty}(-\pi)^n\]

Answer 2

Using root test: \[\lim_{n \rightarrow \infty}\left| \sqrt[n]{(-\pi)^n} \right|=\pi\]Since pi >1, the series diverges by the "Root Test."

Answer 3

lO_Oks good to me