Factor x^2 – 7x + 10, 4x^2 – 81 and p (x) = 3x^3 – 12x
|dw:1481240597579:dw|
|dw:1481240802852:dw|This is one of the way to show ur eqn is right...
ur quadractic expression*
\((x-5)(x-2)\)
u can also double check ur quadractic expression by opening the bracket... \(\color{red}{(}x-5\color{red}{)}\color{red}{(}x-2\color{red}{)}\)
this quadractic expression is a bit special...
\(4x^{2}-81\)
to factor that expression u will need to use this formula which is
\(a^2-b^2=(a\color{red}{-}b)(a\color{red}{+}b)\)
let's see... \(\color{red}{4}x^{2}-\color{red}{81}\)
we could try an exponent of 2...
\(2^{2}x^{2}-9^{2}\)
\(2^\color{red}{2}x^\color{red}{2}-9^\color{red}{2}\)
since,all has the same exponent,it will be easier for us to factor that quadractic expression by using the formula \(a^{2}-b^{2}=(a-b)(a+b)\)
@simplymariex
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