Question

identify the center and radius of a circle with equation (x+4)^2+(y-2)^2 =36

Answer 1

\[(x-h)^2+(y-k)^2=r^2\]

is a circle centered at (h,k) with radius r

Answer 2

you have \[(x+4)^2+(y-2)^2 =36\] which is the same as

\[(x-(-4))^2+(y-2)^2 =6^2\]

Answer 3

Thank you