Question

PLEASE HELP WILL FAN AND MEDAL!!! I NEED TO KNOW HOW TO SOLVE THIS QUESTION! ATTACHING PIC:)

Answer 1

C

Answer 2

could you explain the steps to me?:)

Answer 3

step 1 : y^2 + 7y - 6 = 0

Answer 4

step 2: by using the equation for quadratic ax^2 + bx + c = 0

x1 = {-b + sqrt(b^2 - 4ac) }/2a
x2 = {-b - sqrt(b^2 - 4ac) }/2a

Answer 5

could you explain step 2 to me a little more? whats sqrt?

Answer 6

so,

y1 = { -7 + sqrt(49-24)/ 2 x 1}/ 2 x 1 = -1
y1 = { -7 - sqrt(49-24)/ 2 x 1}/ 2 x 1 = -6

there you go!

Answer 7

sqrt means something to the power 1/2

Answer 8

ok thank you so much!

Answer 9

i hve one more question, if i were ot put that in a calculator, how would i put sqrt in? @babu

Answer 10

sorry for keeping you so long lol @babu

Answer 11

@babu

Answer 12

what model do you use? it should look like this on a regular scientific calculator

Answer 13

ok so how would the whole thing look on a calculator? im trying to figure out how to put it in.. im using the same calculator as you right now. i dont know about the / and the sqrt. could you show me how it would look? like just out in the y1=.... stuff. THANK YOU SO MUCH :)

Answer 14

@babu sorry lol last thing and then I promise ill let ya go

Answer 15

@macabbey101 would you please tell me, which calculator do you use? i use a casia fx-991 ES
please note that, you need a scientific calculator to solve a quadratic equation

Answer 16

*casio