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I need some trig help please!
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\[\cos(3\theta)=-1\]
what's the question?
To find the solution set
2/3 pi
On the interval 0 to 2pi
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If it was \(\large\rm \cos(\theta)=-1\) would you know how to find the solution set for theta? :)
I would look at a unit circle or do arrcos in the calculator?
Cos is =1 at pi
sin(pi) = 1
|dw:1481507239365:dw|Sure :) you could look at a unit circle. cosine is -1 at pi, yes.
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