Question

calculate the difference between in the temperature between the wate at the top and bottom of a water fall 200 m high.Specific heat of water is 4200J Kg^-1C^-1

Answer 1

The loss in PE of 1kg of water falling this distance is mgh

This energy ids mostly converted to heat - we assume in htis case that it ALL is

so when oyu know the energy lost for 1kg you can use

Q = c m (T2-T1)

(Q = energy added)
c = Specific heat capoacity
T2 = final temperature
T1 = initial temperature

(hint it is T2-T1 that is your answer, i.e the change in temperature)