Question

Factor completely 3x3 + 12x2 + 18x.

Answer 1

\[f(x)=3x^3+12x^2+18x\]
Step one* Factor out an x & a 3
\[f(x)=3x(x^2+4x+6)\]

Answer 2

& \[x^2+4x+6\] is unfactorable -->
CHECK: if discriminant is perfect square than it's factorable
\[b^2-4ac\]
a=1 b=4 c=6
*plug in
= (-8)

(: