Question

Suppose F(x)= k(2-x-x^3) has an inverse function and that f^-1 (3)= -2. Find k ?

Answer 1

\[f(x)=k(2-x-x^3)\]
\[f^{-1}(3)=-2\]
so...
f(-2)=3
\[3=k(2-(-2)-(-2)^3)\]
*Solve for k
k=3/8

Answer 2

Thanks a lot, i thought i had it wrong for sec. Thank u again