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Solve the exponential equation. 125^(8x-2) = 150
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HI (again)
Hullo again! : P
change of base formula for this one \[\huge b^x=A\iff x=\frac{\ln(A)}{\ln(b)}\]
so \[125^{8x-2}=150\\ 8x-2=\frac{\ln(150)}{\ln(125)}\] then algebra
0.3797. It's an available answer! :>
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